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Resolvedmysql

"🤔 MySQL Error 1690: Why Does BIGINT UNSIGNED Subtraction Fail? 💾"

技术控老刘

5/11/2025

3 views2 likes

Hey MySQL folks! 😅 I'm hitting this super weird Error 1690 and it's driving me nuts - can anyone spot what I'm missing here?

Here's the situation:

  • Table has a STEP_ID column defined as BIGINT UNSIGNED
  • Data looks fine (showing screenshots in original post)
  • When I run this simple subtraction:
SELECT `NAME`, 202000 - STEP_ID FROM my_table WHERE `Name` = 'aaa';

Boom 💥 - Error 1690: "BIGINT UNSIGNED value is out of range in '(202000 - my_db.my_table.STEP_ID)'"

The crazy part? If I manually enter the actual value instead of using the column name, it works fine! 🤯

Here's everything I've tried (and failed) so far:

-- Attempt 1: Casting just the STEP_ID SELECT `NAME`, 202000 - CAST(STEP_ID AS UNSIGNED) FROM my_table WHERE `Name` = 'aaa'; -- Attempt 2: Casting just the literal SELECT `NAME`, CAST(202000 AS UNSIGNED) - STEP_ID FROM my_table WHERE `Name` = 'aaa'; -- Attempt 3: Double casting both sides SELECT `NAME`, CAST(202000 AS UNSIGNED) - CAST(STEP_ID AS UNSIGNED) FROM my_table WHERE `Name` = 'aaa'; -- And like 3 more variations that all failed the same way 😭

This seems like such a simple operation - why is MySQL freaking out about unsigned ranges when I'm just subtracting numbers? Is there some implicit type conversion voodoo happening?

PS: Working on a deadline (aren't we all? 😩) so any quick insights would be massively appreciated! 🙏

#MySQL #DatabaseProblems #TypeConversion #HelpABrotherOut

1 Answers

开发者老张

5/11/2025

Best Answer14

Answer #1 - Best Answer

Hey there! 👋 Oh man, I feel your pain with this MySQL unsigned integer madness - I've faceplanted into this exact same error more times than I'd like to admit! 😅 It's one of those "looks simple but bites you" MySQL quirks.

Here's the deal - when you subtract a BIGINT UNSIGNED from a regular integer, MySQL gets nervous about potential negative results (which can't exist in unsigned land). Even though your actual values might be fine, MySQL does the type checking before looking at the data. Classic case of "theoretical vs actual" mismatch!

Here's what always works for me:

-- The magic sauce: Cast to signed first! SELECT `NAME`, 202000 - CAST(STEP_ID AS SIGNED) FROM my_table WHERE `Name` = 'aaa';

Or if you prefer the cleaner syntax:

-- Using the shorter form SELECT `NAME`, 202000 - (STEP_ID + 0) FROM my_table WHERE `Name` = 'aaa';

Pro tip from my battle scars: ⚠️ Watch out for these landmines:

  1. Any arithmetic with unsigned columns can trigger this
  2. The error appears even if your actual data would produce valid results
  3. MySQL 8.0 is actually stricter about this than older versions

Fun fact: This is why many devs (myself included) often avoid UNSIGNED for numeric IDs unless absolutely necessary. The "unsigned tax" in query complexity isn't always worth it!

Hang in there - you're definitely not alone in this struggle! 🙌 If you're still seeing weirdness, try checking the actual STEP_ID value with:

SELECT STEP_ID FROM my_table WHERE `Name` = 'aaa' LIMIT 1;

Sometimes there's a sneaky NULL or unexpected value hiding in there. Let me know if you need more help debugging - we'll get this sorted! 💪

#MySQLSolutions #DatabaseDebugging #TypeCasting #QueryOptimization

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